$x ^ 2 - 7x + 6 = 0 , x ^ 2 - (p + 1) x + p = 0$ সমীকরণের সাধারণ মান কত?

$\begin{array}{l}x^{2}-7 x+6=0 \ldots \ldots (i) \\x^{2}-(p+1) x+p=0 \ldots (ii)\end{array}$ $\begin{array}{l}\text { (i) }- \text { (ii) } \\\Rightarrow \mathrm{x}^{2}-7 \mathrm{x}+6-\mathrm{x}^{2}+(\mathrm{p}+1) \mathrm{x}-\mathrm{p}=0 \\\Rightarrow(\mathrm{p}+1-7) \mathrm{x}-\mathrm{p}+6=0 \\\Rightarrow(\mathrm{p}-6) \mathrm{x}-1(\mathrm{p}-6)=0 \\\Rightarrow(\mathrm{p}-6)(\mathrm{x}-1)=0 \\\therefore \mathrm{p}=6 \text { , } \mathrm{x}=1\end{array}$