$\overrightarrow{r}=3×\hat{i}-2y\hat{j}+4z\hat{k}$ হলে $\overrightarrow{∇.}\overrightarrow{r}$ =?

$\overrightarrow{r}=3\hat{i}-2y\hat{j}+4z\hat{k}$ $\overrightarrow{∇} = \frac{∂}{∂x}\hat{i} + \frac{∂}{∂y}\hat{j} + \frac{∂}{∂z}\hat{k}$ $\overrightarrow{∇.}\overrightarrow{r} = (\frac{∂}{∂x}\hat{i} + \frac{∂}{∂y}\hat{j} + \frac{∂}{∂z}\hat{k}).(3\hat{i}-2y\hat{j}+4z\hat{k})$ $\overrightarrow{∇.}\overrightarrow{r} = \frac{∂}{∂x}(3) + \frac{∂}{∂y}(-2y) + \frac{∂}{∂z}(4z)$ $\overrightarrow{∇.}\overrightarrow{r} = 0 - 2 + 4$ $\overrightarrow{∇.}\overrightarrow{r} = 2$