$x^{2}\left(2 x+\frac{1}{2 x}\right)^{10}$ এর বিস্তৃতিতে x-বর্জিত পদ কোনটি?

$x^{2}\left(2 x+\frac{1}{2 x}\right)^{10}$ এর বিস্তৃতিতে $\mathrm{T}_{\mathrm{r}+1}$ তম পদ । $T_{r+1}=x^{2}$ $\times{ }^{10} C_{r} \times(2 x)^{10-r}$ $\times\left(\frac{1}{2 x}\right)^{r}$ $=x^{2} \times{ }^{10} C_{r}$ $\times \frac{2^{10}}{4^{r}}$ $\times x^{10-2 r}$ $={ }^{10} C_{r} \times \frac{2^{10}}{4^{r}}$ $\times x^{12-2 r}$ $\therefore 12-2 \mathrm{r}=0$ $\therefore \mathrm{r}=6$ $\therefore \mathrm{T}_{7}={ }^{10} \mathrm{C}_{6}$ $\times \frac{2^{10}}{4^{6}}$ $\times \mathrm{x}^{0}=\frac{105}{2}$